Electrical Principles III by Noel M. Morris (auth.)

By Noel M. Morris (auth.)

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C. motor the current was 15 A at 250 V. 4 m, the speed was 900 rev/min and the spring balance readings were 195 Nand 45 N, respectively. Determine (a) the input and output power and (b) the efficiency of the motor. 1 6 D. C. Machines D. C. c. 1. A magnetic field is established by the field winding on the salient pole system which is fixed to the frame of the machine. ). f. in the conductor WX is from W to X, and in YZ is from Y to Z (hint: use Fleming's righthand rule). s are additive, current flows out of terminal A of the generator.

2, E oc cPn. mJ. C. t I / / / / 7 - - - - - - - - - / / / Q) / 0> e Q) / / Q) cQ) .... <..... 7b. Ifcurrent J L flows The field winding consists 0 f a large number 0 f turns 0 f fine wire, so that the field current has a relatively low value. The basic machine equation, E ex tPn, is obeyed, and if n is maintained constant then E ex tP. f. which gives rise to a small value of field current. d. f. f. f. of self-inductance (L di/dt) of the field winding. The generated voltage continues to rise until the resistance line (R r) intersects the open-circuit characteristic of the generator.

Determine the percentage change in the armature speed from its original value. f. c. 016 Wb and the armature speed is 900 rev/min. f. 002 Wb and the speed is increased to 1200 rev/min. c. 42 m. 7 T (the remaining conductors can be assumed not to be in a magnetic field). Determine the torque produced when the armature current is 20 A. c. c. generator. c. 7 at 440 V. c. generator delivers a current of 70 A at 110 V. Calculate the overall efficiency of the motor-generator set. c. motor the current was 15 A at 250 V.

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