By L S Dent Glasser; International Union of Crystallography
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Additional resources for Symmetry
Example text
We started with one fragment, the whole half sphere; thus the number of fragments is given by Now for the second statement. As we have already said, each of the N great circle halves is cut by the others into N segments. Each one of these segments serves as side to two adjacent fragments. In addition the "equator" is cut up into 2N segments bordering one fragment each. The total number of sides to the fragments is therefore The average number of sides per fragment is and this approaches 4 as N -»oo.
For example or the classical "isoperimetric inequality". The equality holds only when AT is a circle. Other inequalities due to Blaschke and Carleman respectively are In both cases equality holds only for the circle. 36 CHAPTER 2 Suppose we consider circles only and let K be a circle of radius R. Then Hence for any pair of points belonging to the circle, The last two expectations arise in statistics from time to time and have been developed in different ways. We now offer a brief presentation of measure and density for planes in three dimensions (Santalo (1953)).
As we have already said, each of the N great circle halves is cut by the others into N segments. Each one of these segments serves as side to two adjacent fragments. In addition the "equator" is cut up into 2N segments bordering one fragment each. The total number of sides to the fragments is therefore The average number of sides per fragment is and this approaches 4 as N -»oo. , 2-n-N, plus the circumference of the equator; thus the average perimeter of the fragment is 42 CHAPTER 3 or asymptotically it is and the average length of each side is asymptotically We can now suppose that N becomes very large and consider the distribution of regions in a small circle of radius r on the surface of the sphere.