Theory of Sets by Nicolas Bourbaki (auth.)

By Nicolas Bourbaki (auth.)

This is a softcover reprint of the English translation of 1968 of N. Bourbaki's, Théorie des Ensembles (1970).

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For A =+ R is a theorem in fO, by the criterion of deduction, therefore (V Ax)R is a theorem in 'lO by 027 (no. 1) and 035. In practice, we indicate that we are going to use this rule by a phrase such as "Let x be any element such that A". In the theory G' so defined, we seek to prove R. Of course, we cannot assert that R itself is a theorem in G. 037. Let A and R be relations in 'lO and let x be a letter. Let 'lO' be the theory obtained by adjoining the relations A and "not R" to the axioms of 'lO.

For B~ «not A) or B) is a theorem by 07, and therefore "(not A) or B", that is to say A ~ B, is a theorem by 01. 010. if A is a relation in 'CO, then "A or (not A)" is a theorem in 'iV. For "(not A) or A" is a theorem by OS; now use S3 and 01. 011. If A is a relation in 'CO, "A ~ (not not A)" is a theorem in 'iV. For this relation is "(not A) or (not not A)", and the result follows fromOlO. 012. Let A and B be two relations in to. Then the relation (A ~ B) ~ «not B) ~ (not A)) is a theorem in For '{9.

Z I) is a theorem in '(00' say A. But (Tly)(Ulz)A is precisely A relation of the form T = U, where T and U are terms in '(0, is called an equation; a solution (in '(0) of the relation T = U, considered as an equation in a letter x, is therefore (§2, no. 2) a term V in '(0 such that T I V! = U I V! is a theorem in '0. ~ Let T and U be two terms in '(0, and let Xl' X 2, ••• , XII be the letters which appear in T but not in U. If the relation ~ is a theorem in '(0, we say that U can be put in the form T (in '(0).

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